What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest integer? Please explain.
so consecutive intergers are 1 away from each other so the numbers are x,x+1,x+2 if the product (multily) of 2 smaeller is 5 less than 5 times largest so (x times (x+1)) is 5 less than 5 times (x+2) (x times (x+1))=-5+5(x+2) pemdas distribute using distributiver property a(b+c)=ab+ac so x times (x+1)=x^2+x 5(x+2)=5x+10 we have x^2+x=-5+5x+10 add like terms x^2+x=5x+5 subtract (5x+5) from both sides x^2-4x-5=0 factor by find what 2 numbers add to -4 and multply to get -5 numbers are 1 and -5 so we do (x+1)(x-5)=0 sete each to zero x+1=0 x-5=0
x+1=0 sbtract 1 x=-1 we want positie so thisis wrong answer
