annameghan
annameghan
03-10-2017
Mathematics
contestada
click photo for question and options !!!!!
Respuesta :
liemonder
liemonder
03-10-2017
[tex] \sqrt[5]{x} = x^{\frac{1}{5}}\\ \\ \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} =\\ x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}=\\ x^{\frac{4}{5}}[/tex]
so it is the last option
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round it to nearest fifths
