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  • 03-03-2021
  • Mathematics
contestada

Find the margin of error for a 95% confidence interval for μ; n=49,σ = 4.8 Keep all decimal places.

Respuesta :

fichoh
fichoh fichoh
  • 04-03-2021

Answer:

1.344

Step-by-step explanation:

Given that:

n=49,σ = 4.8

Zcritical = 95%

Using the relation :

Margin of Error = Zcritical * sqrt(σ² / n)

Zcritical at 95% = 1.96

Margin of Error = 1.96 * sqrt(4.8² / 49)

Margin of Error = 1.96 * (4.8 / 7)

Margin of Error = 1.96 * 0.6857142

Margin of Error = 1.344

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